[crispy] week 4 solution #409
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wogha95
approved these changes
Sep 8, 2024
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| if(exisingNum.find(num - 1) != exisingNum.end()) { | ||
| continue; | ||
| } | ||
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| length = 1; | ||
| while(exisingNum.find(num + length) != exisingNum.end()) { |
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c++에서 find의 반환값(찾고자하는 값이 없는 경우)가 .end였군요!👍
| bool isPalindrome(string s) { | ||
| string temp = ""; | ||
| for(char c : s) { | ||
| if(isalnum(c)) { |
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오, isalnum 내장 함수에 대해서도 처음 알았네요!
| @@ -0,0 +1,63 @@ | |||
| // time complexity: O(n * m * 3 ^ L), L은 최대 깊이(문자열 길이) | |||
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시간복잡도에서 상하좌우의 4^L이 아닌 3^L로 계산하신 부분에 대해 설명이 궁금합니다!
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기존에 있던 방향은 확인하지 않아서 3^L로 계산했습니다!
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